Peter de Jong Attractors
Written by Paul Bourke
January 1991, Images updated February 2014
Contribution by Robert Rodger.
Evaldraw script: attract.kc
xn+1 = sin(a yn) - cos(b xn)|
yn+1 = sin(c xn) - cos(d yn)
See "The Pattern Book, Fractals, Art, and Nature"
by Clifford Pickover, chapter titled "Swirl".
a = 1.641, b = 1.902, c = 0.316, d= 1.525
a = 0.970, b = -1.899, c = 1.381,d = -1.506
a = 1.4, b = -2.3, c = 2.4, d = -2.1
a = 2.01, b = -2.53, c = 1.61, d = -0.33
a = -2.7, b = -0.09, c = -0.86, d = -2.2
a = -0.827, b = -1.637, c = 1.659, d = -0.943
a = -2.24, b = 0.43, c = -0.65, d = -2.43
a = -2, b = -2, c = -1.2, d = 2
a = -0.709, b = 1.638, c = 0.452, d = 1.740
Question: How are the colour effects here achieved?
The main thing happening here is that I don't draw the attractor to the final image.
Rather I create a large grid of 32 bit (int or float) and instead of drawing into
that in colour I evaluate points on the attractor and just increment each cell of
the grid if the attractor passes through it. So it's essentially a 2D histogram for
occupancy. One wants to evaluate the attractor much more/longer than normal in order
to create a reasonable dynamic range and ultimately smooth colour gradients. I then
save this 2D grid, the process of applying smooth colour gradients comes as a secondary
process ... better than trying to encode the right colour during the generation
process. One can even just save the grid as a 16 or 32 bit raw, open in PhotoShop and
apply custom gradient maps there.
Of course this is "just" a density mapping of the histogram and doesn't immediately
allow for colouring based upon other attributes of the attractor path, such as curvature.
But such attributes can be encoded into the histogram encoding, for example the amount
added to a cell being a function of curvature.
Contribution by Johnny Svensson
xn+1 = d sin(a xn) - sin(b yn)
yn+1 = c cos(a xn) + cos(b yn)
The one ring
a = 1.40, b = 1.56, c = 1.40, d = -6.56